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7n^2-168=-14n
We move all terms to the left:
7n^2-168-(-14n)=0
We get rid of parentheses
7n^2+14n-168=0
a = 7; b = 14; c = -168;
Δ = b2-4ac
Δ = 142-4·7·(-168)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-70}{2*7}=\frac{-84}{14} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+70}{2*7}=\frac{56}{14} =4 $
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